What is (\partial)/(\partial x)(x^2+4x+y^2) ?

The answer to (\partial)/(\partial x)(x^2+4x+y^2) is 2x+4

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(\partial)/(\partial x)(x^2+4x+y^2)

\frac{\partial}{\partial x} (x^{2} + 4 x + y^{2})

2 x + 4

Solution steps

\frac{\partial}{\partial x} (x^{2} + 4 x + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (4 x) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (4 x) = 4

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 x + 4 + 0

Simplify

= 2 x + 4

tan (e^{4 t}) + e^{t a n (4 t)}

x^{^{''}} = - x

y = (2 y^{4} + 2 x) y^{^{'}}

\frac{e ^{2 x}}{sin ( 3 x )}

\int \frac{2 x}{3} d x

What is (\partial)/(\partial x)(x^2+4x+y^2) ?
The answer to (\partial)/(\partial x)(x^2+4x+y^2) is 2x+4