What is the derivative of y=cos(e^{-t^2}) ?

The derivative of y=cos(e^{-t^2}) is 2e^{-t^2}tsin(e^{-t^2})

What is the first derivative of y=cos(e^{-t^2}) ?

The first derivative of y=cos(e^{-t^2}) is 2e^{-t^2}tsin(e^{-t^2})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = cos (e^{- t^{2}})

2 e^{- t^{2}} t sin (e^{- t^{2}})

Solution steps

\frac{d}{d t} (cos (e^{- t^{2}}))

Apply the chain rule:

- sin (e^{- t^{2}}) \frac{d}{d t} (e^{- t^{2}})

= - sin (e^{- t^{2}}) \frac{d}{d t} (e^{- t^{2}})

\frac{d}{d t} (e^{- t^{2}}) = - 2 e^{- t^{2}} t

= - sin (e^{- t^{2}}) (- 2 e^{- t^{2}} t)

Simplify

= 2 e^{- t^{2}} t sin (e^{- t^{2}})

\frac{d}{d x} ((x^{2} + 2) (x^{3} + 1))

\frac{d}{d t} (0.0225 t e^{- 0.0467 t})

\int \frac{x}{9 - 64 x ^{2}} d x

\int_{0}^{16} 1 + 3 x d x

\frac{d}{d x} (ln (x + y - 1))

What is the derivative of y=cos(e^{-t^2}) ?
The derivative of y=cos(e^{-t^2}) is 2e^{-t^2}tsin(e^{-t^2})
What is the first derivative of y=cos(e^{-t^2}) ?
The first derivative of y=cos(e^{-t^2}) is 2e^{-t^2}tsin(e^{-t^2})