What is the derivative of y=(x+2)^2-3 ?

The derivative of y=(x+2)^2-3 is 2x+4

What is the first derivative of y=(x+2)^2-3 ?

The first derivative of y=(x+2)^2-3 is 2x+4

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derivative of

y = (x + 2)^{2} - 3

2 x + 4

Solution steps

\frac{d}{d x} ((x + 2)^{2} - 3)

Simplify

(x + 2)^{2} - 3 : x^{2} + 4 x + 1

= \frac{d}{d x} (x^{2} + 4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 2 x + 4 + 0

Simplify

= 2 x + 4

\int (3 x^{2} + ln (x)) d x

5 x + 4

\int \frac{sin ( 2 x )}{2 + cos ( x )} d x

\int_{- 5}^{5} \frac{y}{25 - y ^{2}} d y

x^{3} (2 x - 1)^{7}

What is the derivative of y=(x+2)^2-3 ?
The derivative of y=(x+2)^2-3 is 2x+4
What is the first derivative of y=(x+2)^2-3 ?
The first derivative of y=(x+2)^2-3 is 2x+4