What is the integral of (x-1)(x+2) ?

The integral of (x-1)(x+2) is (x^3)/3+(x^2)/2-2x+C

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integral of (x-1)(x+2)

\int (x - 1) (x + 2) d x

\frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + C

Solution steps

\int (x - 1) (x + 2) d x

Expand

(x - 1) (x + 2) : x^{2} + x - 2

= \int x^{2} + x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int x d x - \int 2 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int x d x = \frac{x ^{2}}{2}

\int 2 d x = 2 x

= \frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x

Add a constant to the solution

= \frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + C

f (x) = 5 x^{\frac{4}{5}} - 2 x^{\frac{2}{7}}

\frac{1}{x + 5}

\int t (2 t - 3 t) d t

\frac{\partial}{\partial z} (- x y z^{2})

What is the integral of (x-1)(x+2) ?
The integral of (x-1)(x+2) is (x^3)/3+(x^2)/2-2x+C