What is (\partial)/(\partial x)(2x+y-5) ?

The answer to (\partial)/(\partial x)(2x+y-5) is 2

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(\partial)/(\partial x)(2x+y-5)

\frac{\partial}{\partial x} (2 x + y - 5)

2

Solution steps

\frac{\partial}{\partial x} (2 x + y - 5)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (5)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (5) = 0

= 2 + 0 - 0

Simplify

= 2

\frac{d}{d x} (arccos (\frac{y}{x}))

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\int 3 x^{2} (x^{3} + 1)^{6} d x

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What is (\partial)/(\partial x)(2x+y-5) ?
The answer to (\partial)/(\partial x)(2x+y-5) is 2