What is the derivative of 18sqrt(t) ?

The derivative of 18sqrt(t) is 9/(sqrt(t))

What is the first derivative of 18sqrt(t) ?

The first derivative of 18sqrt(t) is 9/(sqrt(t))

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derivative of

18 t

\frac{9}{t}

Solution steps

\frac{d}{d t} (18 t)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 18 \frac{d}{d t} (t)

Apply radical rule:

a = a^{\frac{1}{2}}

= 18 \frac{d}{d t} (t^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 18 \cdot \frac{1}{2} t^{\frac{1}{2} - 1}

Simplify

18 \cdot \frac{1}{2} t^{\frac{1}{2} - 1} : \frac{9}{t}

= \frac{9}{t}

y = - 2 e^{- x^{2}} x

\int \frac{3 x}{1 + x ^{3}} d x

y^{^{'}} + 2 x y = y + 4 x - 2

\frac{d}{d x} (\frac{1}{1 + e ^{x}})

\frac{\partial}{\partial y} (3 x^{2} + y^{2})

What is the derivative of 18sqrt(t) ?
The derivative of 18sqrt(t) is 9/(sqrt(t))
What is the first derivative of 18sqrt(t) ?
The first derivative of 18sqrt(t) is 9/(sqrt(t))