What is the integral from 0 to 0.3 of 600x ?

The integral from 0 to 0.3 of 600x is 27

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integral from 0 to 0.3 of 600x

\int_{0}^{0.3} 600 x d x

27

Solution steps

\int_{0}^{0.3} 600 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 600 \cdot \int_{0}^{0.3} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.3}

= 600 [\frac{x ^{2}}{2}]_{0}^{0.3}

Simplify

= 600 [0.5 x^{2}]_{0}^{0.3}

Compute the boundaries:

0.045

= 600 \cdot 0.045

Simplify

= 27

f (x) = 2 ln (x)

\frac{d}{d x} (ln (\frac{1}{x}))

x \to 2 lim ((5 x + 7)^{4})

\int \frac{x ^{3} + 1}{x + 2} d x

What is the integral from 0 to 0.3 of 600x ?
The integral from 0 to 0.3 of 600x is 27