What is the integral of 3(2x-2)ln(x-2) ?

The integral of 3(2x-2)ln(x-2) is 3(ln(x-2)(x^2-2x)-(x^2)/2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 3(2x-2)ln(x-2)

\int 3 (2 x - 2) ln (x - 2) d x

3 (ln (x - 2) (x^{2} - 2 x) - \frac{x ^{2}}{2}) + C

Solution steps

\int 3 (2 x - 2) ln (x - 2) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int (2 x - 2) ln (x - 2) d x

Apply Integration By Parts

: ln (x - 2) (x^{2} - 2 x) - \int x d x

= 3 (ln (x - 2) (x^{2} - 2 x) - \int x d x)

\int x d x = \frac{x ^{2}}{2}

= 3 (ln (x - 2) (x^{2} - 2 x) - \frac{x ^{2}}{2})

Add a constant to the solution

= 3 (ln (x - 2) (x^{2} - 2 x) - \frac{x ^{2}}{2}) + C

\int 3 x + 1 d x

n = 0 \sum \infty (- \frac{2}{7})^{n}

x^{2} - 4 x + 1, - x + 5

x \to 2 lim (15)

\int e^{- 6 t} d t

What is the integral of 3(2x-2)ln(x-2) ?
The integral of 3(2x-2)ln(x-2) is 3(ln(x-2)(x^2-2x)-(x^2)/2)+C