What is (\partial)/(\partial y)(cos(8x)sin(2y)) ?

The answer to (\partial)/(\partial y)(cos(8x)sin(2y)) is cos(8x)cos(2y)*2

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(\partial)/(\partial y)(cos(8x)sin(2y))

\frac{\partial}{\partial y} (cos (8 x) sin (2 y))

cos (8 x) cos (2 y) \cdot 2

Solution steps

\frac{\partial}{\partial y} (cos (8 x) sin (2 y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (8 x) \frac{\partial}{\partial y} (sin (2 y))

Apply the chain rule:

cos (2 y) \frac{\partial}{\partial y} (2 y)

= cos (2 y) \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (2 y) = 2

= cos (8 x) cos (2 y) \cdot 2

x^{4} - 3 x^{2} + 1

n = 0 \sum \infty \frac{1}{n ^{3} + 1}

7 x^{\frac{1}{5}} (x^{3} - 2)

\frac{d}{d x} (y^{2} (8 - x))

x^{2} y^{^{'}} = 4 x^{2} y^{3} - 2 x y

What is (\partial)/(\partial y)(cos(8x)sin(2y)) ?
The answer to (\partial)/(\partial y)(cos(8x)sin(2y)) is cos(8x)cos(2y)*2