What is (d^2)/(dx^2)(ln(1+e^x)) ?

The answer to (d^2)/(dx^2)(ln(1+e^x)) is (e^x)/((1+e^x)^2)

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(d^2)/(dx^2)(ln(1+e^x))

\frac{d ^{2}}{d x ^{2}} (ln (1 + e^{x}))

\frac{e ^{x}}{( 1 + e ^{x} ) ^{2}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (ln (1 + e^{x}))

\frac{d}{d x} (ln (1 + e^{x})) = \frac{e ^{x}}{1 + e ^{x}}

= \frac{d}{d x} (\frac{e ^{x}}{1 + e ^{x}})

\frac{d}{d x} (\frac{e ^{x}}{1 + e ^{x}}) = \frac{e ^{x}}{( 1 + e ^{x} ) ^{2}}

= \frac{e ^{x}}{( 1 + e ^{x} ) ^{2}}

\frac{\partial}{\partial x} (7 x + 8 y^{2})

\frac{s + 11}{( s - 10 ) ( s + 4 )}

2 e^{- 2 t} cos (7 t) - 5 e^{- 2 t} sin (7 t)

\frac{d}{d x} (\frac{e ^{x}}{x})

n = 0 \sum \infty n + 3

What is (d^2)/(dx^2)(ln(1+e^x)) ?
The answer to (d^2)/(dx^2)(ln(1+e^x)) is (e^x)/((1+e^x)^2)