What is the solution for xy^'+9y=12y^2,y(1)=-1 ?

The solution for xy^'+9y=12y^2,y(1)=-1 is y= 3/(-7x^9+4)

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xy^'+9y=12y^2,y(1)=-1

x y^{^{'}} + 9 y = 12 y^{2}, y (1) = - 1

y = \frac{3}{- 7 x ^{9} + 4}

Solution steps

x y^{'} (x) + 9 y = 12 y^{2}

Solve Bernoulli ODE:

y = \frac{3}{- 7 x ^{9} + 4}

y = \frac{3}{- 7 x ^{9} + 4}

\frac{d}{d x} (x \cdot a)

\int \frac{1}{( x ^{2} + 1 ) ^{4}} d x

\int \frac{2 x + 1}{x ^{2} - x} d x

\frac{d}{d t} (\frac{3 y ^{2} - t ^{2}}{y ^{5}})

\frac{d}{d x} (ln (\frac{4}{x x + 1}))

What is the solution for xy^'+9y=12y^2,y(1)=-1 ?
The solution for xy^'+9y=12y^2,y(1)=-1 is y= 3/(-7x^9+4)