What is the limit as z approaches 0 of 1/(1+z^2) ?

The limit as z approaches 0 of 1/(1+z^2) is 1

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limit as z approaches 0 of 1/(1+z^2)

z \to 0 lim (\frac{1}{1 + z ^{2}})

1

Solution steps

z \to 0 lim (\frac{1}{1 + z ^{2}})

Plug in the value

z = 0

= \frac{1}{1 + 0 ^{2}}

Simplify

= 1

\frac{d}{d x} (\frac{ln ( x ^{2} )}{x})

(t^{2} + 1) f^{^{'}} (t) + [f (t)]^{2} + 1 = 0

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\int_{2}^{5} x^{2} - 6 x + 9 d x

What is the limit as z approaches 0 of 1/(1+z^2) ?
The limit as z approaches 0 of 1/(1+z^2) is 1