What is the derivative of e^{-3t} ?

The derivative of e^{-3t} is -3e^{-3t}

What is the first derivative of e^{-3t} ?

The first derivative of e^{-3t} is -3e^{-3t}

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derivative of

e^{- 3 t}

- 3 e^{- 3 t}

Solution steps

\frac{d}{d t} (e^{- 3 t})

Apply the chain rule:

e^{- 3 t} \frac{d}{d t} (- 3 t)

= e^{- 3 t} \frac{d}{d t} (- 3 t)

\frac{d}{d t} (- 3 t) = - 3

= e^{- 3 t} (- 3)

Simplify

= - 3 e^{- 3 t}

\frac{d}{d x} (lo g_{10} (x^{2} + 1))

\frac{x}{1 + x ^{2}}, at x = - 1

y = 2 - x, y = 4 - x^{2}

\int (x^{2} + e^{1 - x}) d x

y^{^{''}} + 2 y + y = x e^{- x}

What is the derivative of e^{-3t} ?
The derivative of e^{-3t} is -3e^{-3t}
What is the first derivative of e^{-3t} ?
The first derivative of e^{-3t} is -3e^{-3t}