What is area y=5x^2,y=x^2+2 ?

The answer to area y=5x^2,y=x^2+2 is -(2sqrt(2))/3+2sqrt(2)

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area y=5x^2,y=x^2+2

area

y = 5 x^{2}, y = x^{2} + 2

- \frac{2 2}{3} + 22

Decimal Notation

1.88561 \dots

Solution steps

Apply the area formula:

\int_{- \frac{1}{2}}^{\frac{1}{2}} 5 x^{2} - (x^{2} + 2) d x

Solve

\int_{- \frac{1}{2}}^{\frac{1}{2}} 5 x^{2} - (x^{2} + 2) d x : - \frac{2 2}{3} + 22

The area is:

= - \frac{2 2}{3} + 22

x \to 0 lim (x e^{- \frac{1}{x ^{2}}})

\frac{d}{d x} (ln (3 x^{3} + 4 x^{2} + x + 4))

\frac{d}{d t} (\frac{e ^{2 t}}{1 - t ^{2}})

\frac{d}{d x} (\frac{x}{x ^{- 1} + 3})

\frac{d}{d x} (cos (\frac{3}{2} x))

What is area y=5x^2,y=x^2+2 ?
The answer to area y=5x^2,y=x^2+2 is -(2sqrt(2))/3+2sqrt(2)