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Popular >

integral from 0 to 4 of (2x+5)

Solution

\int_{0}^{4} (2 x + 5) d x

Solution

36

Solution steps

\int_{0}^{4} 2 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 2 x d x + \int_{0}^{4} 5 d x

\int_{0}^{4} 2 x d x = 16

\int_{0}^{4} 5 d x = 20

= 16 + 20

Simplify

= 36

Popular Examples

derivative of x^2f(x)derivative of

x^{2} f (x)

integral of 1/(-\frac{1){x^2}+2x}-3

\int \frac{1}{- \frac{1}{x ^{2}} + 2 x} - 3 d x

inverse oflaplace 1/((s^2+4)^2*s)inverse laplace

\frac{1}{( s ^{2} + 4 ) ^{2} \cdot s}

tangent of f(x)=x^3ln(2x),\at x=5 tangent of

f (x) = x^{3} ln (2 x), at x = 5

limit as x approaches 1 of 1-(x-1)^2

x \to 1 lim (1 - (x - 1)^{2})

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (2x+5) ?
The integral from 0 to 4 of (2x+5) is 36