What is the integral from 0 to pi/(12) of cos(4x) ?

The integral from 0 to pi/(12) of cos(4x) is (sqrt(3))/8

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integral from 0 to pi/(12) of cos(4x)

\int_{0}^{\frac{π}{12}} cos (4 x) d x

\frac{3}{8}

Decimal Notation

0.21650 \dots

Solution steps

\int_{0}^{\frac{π}{12}} cos (4 x) d x

Apply u-substitution

: \int_{0}^{\frac{π}{3}} cos (u) \frac{1}{4} d u

= \int_{0}^{\frac{π}{3}} cos (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{0}^{\frac{π}{3}} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{4} [sin (u)]_{0}^{\frac{π}{3}}

Compute the boundaries:

\frac{3}{2}

= \frac{1}{4} \cdot \frac{3}{2}

Simplify

= \frac{3}{8}

f (x) = sin^{3} (18 x)

x \to 3 lim (x^{2} - 7)

x \to + 0 + lim (\frac{0}{x})

x \to 3 lim (cos (x))

f (x) = 1 + x^{2}

What is the integral from 0 to pi/(12) of cos(4x) ?
The integral from 0 to pi/(12) of cos(4x) is (sqrt(3))/8