What is the integral from 0 to pi/7 of cos(4x) ?

The integral from 0 to pi/7 of cos(4x) is 1/4 sin((4pi)/7)

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integral from 0 to pi/7 of cos(4x)

\int_{0}^{\frac{π}{7}} cos (4 x) d x

\frac{1}{4} sin (\frac{4 π}{7})

Decimal Notation

0.24373 \dots

Solution steps

\int_{0}^{\frac{π}{7}} cos (4 x) d x

Apply u-substitution

: \int_{0}^{\frac{4 π}{7}} cos (u) \frac{1}{4} d u

= \int_{0}^{\frac{4 π}{7}} cos (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{0}^{\frac{4 π}{7}} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{4} [sin (u)]_{0}^{\frac{4 π}{7}}

Compute the boundaries:

sin (\frac{4 π}{7})

= \frac{1}{4} sin (\frac{4 π}{7})

\int x^{2} + 1 d x

\frac{d}{d x} (e^{2 x - x^{2}})

n = 0 \sum \infty \frac{6 ^{n}}{n + 1}

x \to - \frac{7 π}{2} + lim (sec (x))

\int (x^{2} + 7) \cdot ln (x) d x

What is the integral from 0 to pi/7 of cos(4x) ?
The integral from 0 to pi/7 of cos(4x) is 1/4 sin((4pi)/7)