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Popular >

e^{5y}y^'=x^3

Solution

e^{5 y} y^{^{'}} = x^{3}

Solution

y = \frac{ln ( \frac{5 x ^{4}}{4} + c _{1} )}{5}

Solution steps

e^{5 y} y^{'} (x) = x^{3}

Solve separable ODE:

y = \frac{ln ( \frac{5 x ^{4}}{4} + c _{1} )}{5}

y = \frac{ln ( \frac{5 x ^{4}}{4} + c _{1} )}{5}

Popular Examples

integral of (5x+1)^{19}

\int (5 x + 1)^{19} d x

limit as x approaches 2+of x/(2-x)

x \to 2 + lim (\frac{x}{2 - x})

tangent of y=e^{4x}tangent of

y = e^{4 x}

y^{''}+y^'= 1/4 cos(3t)

y^{^{''}} + y^{^{'}} = \frac{1}{4} cos (3 t)

(\partial)/(\partial x)(e^{2y-x})

\frac{\partial}{\partial x} (e^{2 y - x})

Frequently Asked Questions (FAQ)

What is the solution for e^{5y}y^'=x^3 ?
The solution for e^{5y}y^'=x^3 is y=(ln((5x^4)/4+c_{1}))/(5)