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Popular >

xy^'+y=-8xy^2,y(1)=1

Solution

x y^{^{'}} + y = - 8 x y^{2}, y (1) = 1

Solution

y = \frac{1}{x ( 8 ln ( x ) + 1 )}

Solution steps

x y^{'} (x) + y = - 8 x y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ( 8 ln ( x ) + 1 )}

y = \frac{1}{x ( 8 ln ( x ) + 1 )}

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Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=-8xy^2,y(1)=1 ?
The solution for xy^'+y=-8xy^2,y(1)=1 is y= 1/(x(8ln(x)+1))