What is the solution for y^'-6/x y=(y^4)/(x^3) ?

The solution for y^'-6/x y=(y^4)/(x^3) is y=(2\sqrt[3]{2}x^6)/(\sqrt[3]{-3x^{16)+c_{1}}}

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y^'-6/x y=(y^4)/(x^3)

y^{^{'}} - \frac{6}{x} y = \frac{y ^{4}}{x ^{3}}

Solution steps

y^{'} (x) - \frac{6}{x} y = \frac{y ^{4}}{x ^{3}}

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\int e^{x} 2 x d x

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What is the solution for y^'-6/x y=(y^4)/(x^3) ?
The solution for y^'-6/x y=(y^4)/(x^3) is y=(2\sqrt[3]{2}x^6)/(\sqrt[3]{-3x^{16)+c_{1}}}