What is the derivative of f(x)=2ln(6+x) ?

The derivative of f(x)=2ln(6+x) is 2/(6+x)

What is the first derivative of f(x)=2ln(6+x) ?

The first derivative of f(x)=2ln(6+x) is 2/(6+x)

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derivative of

f (x) = 2 ln (6 + x)

\frac{2}{6 + x}

Solution steps

\frac{d}{d x} (2 ln (6 + x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (ln (6 + x))

Apply the chain rule:

\frac{1}{6 + x} \frac{d}{d x} (6 + x)

= \frac{1}{6 + x} \frac{d}{d x} (6 + x)

\frac{d}{d x} (6 + x) = 1

= 2 \cdot \frac{1}{6 + x} \cdot 1

Simplify

2 \cdot \frac{1}{6 + x} \cdot 1 : \frac{2}{6 + x}

= \frac{2}{6 + x}

\frac{d}{d x} (\frac{3}{lo g _{8} ( x )})

x \cdot y^{^{'}} - y = \frac{5}{4} \cdot x \cdot ln (x)

\int \frac{x}{1 + 2 x ^{2}} d x

\frac{d y}{d x} + y (1 - 2 x) = - \frac{x ^{2}}{2} y

\int 50 + 3 x^{2} - \frac{3}{2} x d x

What is the derivative of f(x)=2ln(6+x) ?
The derivative of f(x)=2ln(6+x) is 2/(6+x)
What is the first derivative of f(x)=2ln(6+x) ?
The first derivative of f(x)=2ln(6+x) is 2/(6+x)