What is the limit as x approaches 1+of (3x)/(x^2-1) ?

The limit as x approaches 1+of (3x)/(x^2-1) is infinity

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limit as x approaches 1+of (3x)/(x^2-1)

x \to 1 + lim (\frac{3 x}{x ^{2} - 1})

\infty

Solution steps

x \to 1 + lim (\frac{3 x}{x ^{2} - 1})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 3 \cdot x \to 1 + lim (\frac{x}{x ^{2} - 1})

\frac{x}{x ^{2} - 1} = x \frac{1}{x ^{2} - 1}

= 3 \cdot x \to 1 + lim (x \frac{1}{x ^{2} - 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= 3 \cdot x \to 1 + lim (x) \cdot x \to 1 + lim (\frac{1}{x ^{2} - 1})

x \to 1 + lim (x) = 1

x \to 1 + lim (\frac{1}{x ^{2} - 1}) = \infty

= 3 \cdot 1 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

\int (1 + (\frac{1}{4 x ^{\frac{2}{3}}})) d x

\frac{d y}{d x} = 2 y - 2 y^{5}

n = 0 \sum \infty \frac{1}{( n + 1 ) ^{2}}

\int \frac{ln ( x ) + 1}{x ^{2}} d x

What is the limit as x approaches 1+of (3x)/(x^2-1) ?
The limit as x approaches 1+of (3x)/(x^2-1) is infinity