What is the integral of sin(5pix) ?

The integral of sin(5pix) is -1/(5pi)cos(5pix)+C

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integral of sin(5pix)

\int sin (5 π x) d x

- \frac{1}{5 π} cos (5 π x) + C

Solution steps

\int sin (5 π x) d x

Apply u-substitution

: \int sin (u) \frac{1}{5 π} d u

= \int sin (u) \frac{1}{5 π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5 π} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{5 π} (- cos (u))

Substitute back

u = 5 π x

= \frac{1}{5 π} (- cos (5 π x))

Simplify

= - \frac{1}{5 π} cos (5 π x)

Add a constant to the solution

= - \frac{1}{5 π} cos (5 π x) + C

4 x^{\frac{1}{2}}

9 y^{^{''}} + 42 y^{^{'}} + 49 y = 0

\frac{d}{d x} (a + b x + c x^{2} + d x^{3})

x \to 7 lim (- 11)

x^{- \frac{1}{9}}

What is the integral of sin(5pix) ?
The integral of sin(5pix) is -1/(5pi)cos(5pix)+C