What is the tangent of f(x)=x^2-2,(3,7) ?

The tangent of f(x)=x^2-2,(3,7) is y=6x-11

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tangent of f(x)=x^2-2,(3,7)

tangent of

f (x) = x^{2} - 2, (3, 7)

y = 6 x - 11

Solution steps

Find the slope of

f (x) = x^{2} - 2 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 2

(3, 7) : m = 6

Find the line with slope m=

6

and passing through

(3, 7) : y = 6 x - 11

y = 6 x - 11

\frac{\partial}{\partial y} ((x y + 1)^{2})

x \to 0 lim ((c e^{x} + 1) i f)

f (x) = 5 x^{4} + \frac{1}{2 x ^{2}}

\frac{d}{d x} (\frac{1}{( ln ( x ) ) ^{3}})

\int \frac{x ^{2} + 3}{x + 1} d x

What is the tangent of f(x)=x^2-2,(3,7) ?
The tangent of f(x)=x^2-2,(3,7) is y=6x-11