What is the derivative of (4x/(x-3)) ?

The derivative of (4x/(x-3)) is -(12)/((x-3)^2)

What is the first derivative of (4x/(x-3)) ?

The first derivative of (4x/(x-3)) is -(12)/((x-3)^2)

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\frac{d}{d x} (\frac{4 x}{x - 3})

- \frac{12}{( x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x}{x - 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{x - 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} ( x - 3 ) - \frac{d}{d x} ( x - 3 ) x}{( x - 3 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x - 3) = 1

= 4 \cdot \frac{1 \cdot ( x - 3 ) - 1 \cdot x}{( x - 3 ) ^{2}}

Simplify

4 \cdot \frac{1 \cdot ( x - 3 ) - 1 \cdot x}{( x - 3 ) ^{2}} : - \frac{12}{( x - 3 ) ^{2}}

= - \frac{12}{( x - 3 ) ^{2}}

x y^{2} y^{^{'}} = y^{3} - 3 x^{3}, y (1) = 3

\frac{x - 2}{x + 2}

\int x e^{9 - x^{2}} d x

(2 x^{2} + y^{2}) d x - x^{2} d y = 0

\int (x - 5) ln (x) d x

What is the derivative of (4x/(x-3)) ?
The derivative of (4x/(x-3)) is -(12)/((x-3)^2)
What is the first derivative of (4x/(x-3)) ?
The first derivative of (4x/(x-3)) is -(12)/((x-3)^2)