What is derivative of f(x)=(4t-5)^4+(4t+5)^4 ?

The answer to derivative of f(x)=(4t-5)^4+(4t+5)^4 is (dt)/(dx)=0

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derivative of f(x)=(4t-5)^4+(4t+5)^4

derivative of

f (x) = (4 t - 5)^{4} + (4 t + 5)^{4}

\frac{d t}{d x} = 0

Solution steps

f (x) = (4 t - 5)^{4} + (4 t + 5)^{4}

Treat

t

t (x)

Differentiate both sides:

0 = 2048 t^{3} \frac{d t}{d x} + 9600 t \frac{d t}{d x}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

y = [x (x^{5} + 4)^{4}]

\int \frac{6}{3 x + 1} d x

x \to \infty + lim (\frac{1}{lo g _{10} ( x )})

\frac{1}{( - x ^{2} + x - 2 ) ^{5}}

x^{2} - 3, at x = 2

What is derivative of f(x)=(4t-5)^4+(4t+5)^4 ?
The answer to derivative of f(x)=(4t-5)^4+(4t+5)^4 is (dt)/(dx)=0