What is (\partial)/(\partial x)(-3cos(3x)) ?

The answer to (\partial)/(\partial x)(-3cos(3x)) is 9sin(3x)

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(\partial)/(\partial x)(-3cos(3x))

\frac{\partial}{\partial x} (- 3 cos (3 x))

9 sin (3 x)

Solution steps

\frac{\partial}{\partial x} (- 3 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{\partial}{\partial x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{\partial}{\partial x} (3 x)

= - sin (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= - 3 (- sin (3 x) \cdot 3)

Simplify

= 9 sin (3 x)

\int_{6}^{8} \frac{80}{( x - 6 ) ^{3}} d x

\frac{\partial}{\partial y} (x^{2} - y^{3} + 5 x + 12 y + 1)

2 x^{2} + 3

\int (e^{7 x}) d x

x \to 0 + lim (2 x)

What is (\partial)/(\partial x)(-3cos(3x)) ?
The answer to (\partial)/(\partial x)(-3cos(3x)) is 9sin(3x)