What is the tangent of f(x)=x+sqrt(x),(49,56) ?

The tangent of f(x)=x+sqrt(x),(49,56) is y= 15/14 x+7/2

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tangent of f(x)=x+sqrt(x),(49,56)

tangent of

f (x) = x + x, (49, 56)

y = \frac{15}{14} x + \frac{7}{2}

Solution steps

Find the slope of

f (x) = x + x : \frac{df ( x )}{d x} = 1 + \frac{1}{2 x}

Compute the slope of

f (x) = x + x

(49, 56) : m = \frac{15}{14}

Find the line with slope m=

\frac{15}{14}

and passing through

(49, 56) : y = \frac{15}{14} x + \frac{7}{2}

y = \frac{15}{14} x + \frac{7}{2}

y = x

\int 1 + x + 5 x^{2} d x

f (x) = \frac{1 - x e ^{x}}{x + e ^{x}}

k = 1 \sum \infty (- 1)^{k}

\frac{d}{d x} (\frac{x - 3}{3})

What is the tangent of f(x)=x+sqrt(x),(49,56) ?
The tangent of f(x)=x+sqrt(x),(49,56) is y= 15/14 x+7/2