What is the derivative of ln(4+x^2) ?

The derivative of ln(4+x^2) is (2x)/(4+x^2)

What is the first derivative of ln(4+x^2) ?

The first derivative of ln(4+x^2) is (2x)/(4+x^2)

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\frac{d}{d x} (ln (4 + x^{2}))

\frac{2 x}{4 + x ^{2}}

Solution steps

\frac{d}{d x} (ln (4 + x^{2}))

Apply the chain rule:

\frac{1}{4 + x ^{2}} \frac{d}{d x} (4 + x^{2})

= \frac{1}{4 + x ^{2}} \frac{d}{d x} (4 + x^{2})

\frac{d}{d x} (4 + x^{2}) = 2 x

= \frac{1}{4 + x ^{2}} \cdot 2 x

Simplify

\frac{1}{4 + x ^{2}} \cdot 2 x : \frac{2 x}{4 + x ^{2}}

= \frac{2 x}{4 + x ^{2}}

y^{^{'}} - 5 y = 9 e^{8 t}

\int \frac{2}{2 x + 3} d x

y^{^{''}} + 4 y^{^{'}} + 5 y = 35 e^{- 4 x}, y (0) = - 3, y^{^{'}} (0) = 1

4 x^{^{'}} + x = 5

\frac{d y}{d t} + 0.1 t y = 2 t, y (0) = 3

What is the derivative of ln(4+x^2) ?
The derivative of ln(4+x^2) is (2x)/(4+x^2)
What is the first derivative of ln(4+x^2) ?
The first derivative of ln(4+x^2) is (2x)/(4+x^2)