What is the tangent of y=x^4+7e^x,(0,7) ?

The tangent of y=x^4+7e^x,(0,7) is y=7x+7

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tangent of y=x^4+7e^x,(0,7)

tangent of

y = x^{4} + 7 e^{x}, (0, 7)

y = 7 x + 7

Solution steps

Find the slope of

y = x^{4} + 7 e^{x} : \frac{d y}{d x} = 4 x^{3} + 7 e^{x}

Compute the slope of

y = x^{4} + 7 e^{x}

(0, 7) : m = 7

Find the line with slope m=

7

and passing through

(0, 7) : y = 7 x + 7

y = 7 x + 7

\int \frac{x}{9 + x ^{4}} d x

ln (16 sin^{2} (x))

x \to 7 + lim (\frac{1}{( x - 7 ) ^{2}})

\frac{9 x ^{2}}{6 + x ^{3}}

\int \frac{1}{x - 1 + x ^{2}} d x

What is the tangent of y=x^4+7e^x,(0,7) ?
The tangent of y=x^4+7e^x,(0,7) is y=7x+7