What is (\partial)/(\partial y)(cos(yz)) ?

The answer to (\partial)/(\partial y)(cos(yz)) is -sin(yz)z

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(\partial)/(\partial y)(cos(yz))

\frac{\partial}{\partial y} (cos (yz))

- sin (yz) z

Solution steps

\frac{\partial}{\partial y} (cos (yz))

Treat

z

as a constant

Apply the chain rule:

- sin (yz) \frac{\partial}{\partial y} (yz)

= - sin (yz) \frac{\partial}{\partial y} (yz)

\frac{\partial}{\partial y} (yz) = z

= - sin (yz) z

(x + 2) sin (y) + (x cos (y)) y^{^{'}} = 0

x \to 0 + lim (ln (0) - \frac{1}{x})

\int_{- 1}^{3} \frac{1}{x ^{2}} d x

y^{^{''}} - 12 y^{^{'}} + 38 y = 0

\int \frac{1}{2} cos^{2} (3 θ) d θ

What is (\partial)/(\partial y)(cos(yz)) ?
The answer to (\partial)/(\partial y)(cos(yz)) is -sin(yz)z