What is the d/(dt)(\sqrt[3]{t}) ?

The d/(dt)(\sqrt[3]{t}) is 1/(3t^{2/3)}

What is the first d/(dt)(\sqrt[3]{t}) ?

The first d/(dt)(\sqrt[3]{t}) is 1/(3t^{2/3)}

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\frac{d}{d t} (3 t)

\frac{1}{3 t ^{\frac{2}{3}}}

Solution steps

\frac{d}{d t} (3 t)

Apply radical rule:

n a = a^{\frac{1}{n}}

= \frac{d}{d t} (t^{\frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} t^{\frac{1}{3} - 1}

Simplify

\frac{1}{3} t^{\frac{1}{3} - 1} : \frac{1}{3 t ^{\frac{2}{3}}}

= \frac{1}{3 t ^{\frac{2}{3}}}

\int x - \frac{1}{2} sin (2 x) d x

\frac{d}{d x} (e^{(2 x)})

\frac{d}{d x} (5 x^{3} ln (x))

\frac{d}{d x} (6 x - x^{2})

y^{^{'}} + y = e^{t} + 11

What is the d/(dt)(\sqrt[3]{t}) ?
The d/(dt)(\sqrt[3]{t}) is 1/(3t^{2/3)}
What is the first d/(dt)(\sqrt[3]{t}) ?
The first d/(dt)(\sqrt[3]{t}) is 1/(3t^{2/3)}