What is (\partial)/(\partial x)(e^{-5x^2-4y^2}) ?

The answer to (\partial)/(\partial x)(e^{-5x^2-4y^2}) is -10e^{-5x^2-4y^2}x

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(\partial)/(\partial x)(e^{-5x^2-4y^2})

\frac{\partial}{\partial x} (e^{- 5 x^{2} - 4 y^{2}})

- 10 e^{- 5 x^{2} - 4 y^{2}} x

Solution steps

\frac{\partial}{\partial x} (e^{- 5 x^{2} - 4 y^{2}})

Treat

y

as a constant

Apply the chain rule:

e^{- 5 x^{2} - 4 y^{2}} \frac{\partial}{\partial x} (- 5 x^{2} - 4 y^{2})

= e^{- 5 x^{2} - 4 y^{2}} \frac{\partial}{\partial x} (- 5 x^{2} - 4 y^{2})

\frac{\partial}{\partial x} (- 5 x^{2} - 4 y^{2}) = - 10 x

= e^{- 5 x^{2} - 4 y^{2}} (- 10 x)

Simplify

= - 10 e^{- 5 x^{2} - 4 y^{2}} x

f (x) = ln (\frac{x}{x ^{2} + 1})

x \to 3 - lim (e^{\frac{2}{x - 3}})

\int 5^{t} sin (5^{t}) d t

\int x (ln^{2} (x)) d x

n = 1 \sum \infty (\frac{n}{n + 10})^{n}

What is (\partial)/(\partial x)(e^{-5x^2-4y^2}) ?
The answer to (\partial)/(\partial x)(e^{-5x^2-4y^2}) is -10e^{-5x^2-4y^2}x