2xy^'=y^2

الحلّ

2 x y^{^{'}} = y^{2}

y = - \frac{2}{ln ( x ) + c _{1}}

خطوات الحلّ

2 x y^{'} (x) = y^{2}

Solve separable ODE:

y = - \frac{2}{ln ( x ) + c _{1}}

y = - \frac{2}{ln ( x ) + c _{1}}

\int cos^{2} (u) d u

\int_{0}^{25} x d x

x y^{^{'}} = x^{3} + 17 x^{3} y

\frac{d}{d z} (csc (arcsin (z^{2})))

\frac{d}{d x} (ln (arctan (8 x^{3})))