en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=2x,y=sqrt(x)

Solution

area

y = 2 x, y = x

Solution

\frac{1}{48}

+1

Decimal

0.02083 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{1}{4}} 2 x - x d x

Solve

\int_{0}^{\frac{1}{4}} 2 x - x d x : \frac{1}{48}

The area is:

= \frac{1}{48}

Graph

Popular Examples

derivative of sec(2x^3)

\frac{d}{d x} (sec (2 x^{3}))

derivative of (x-2/x+ln(x/2))

\frac{d}{d x} (\frac{x - 2}{x} + ln (\frac{x}{2}))

integral from-infinity to 5 of xe^x

\int_{- \infty}^{5} x e^{x} d x

1/((1+2y^2))y^'=csc(x)

\frac{1}{( 1 + 2 y ^{2} )} y^{^{'}} = csc (x)

limit as x approaches 0 of (x+e^{x/6})^{6/x}

x \to 0 lim ((x + e^{\frac{x}{6}})^{\frac{6}{x}})

Frequently Asked Questions (FAQ)

What is area y=2x,y=sqrt(x) ?
The answer to area y=2x,y=sqrt(x) is 1/48