What is the derivative of (4x^5+7/(x^3)) ?

The derivative of (4x^5+7/(x^3)) is (8x^5-21)/(x^4)

What is the first derivative of (4x^5+7/(x^3)) ?

The first derivative of (4x^5+7/(x^3)) is (8x^5-21)/(x^4)

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\frac{d}{d x} (\frac{4 x ^{5} + 7}{x ^{3}})

\frac{8 x ^{5} - 21}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{4 x ^{5} + 7}{x ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x ^{5} + 7 ) x ^{3} - \frac{d}{d x} ( x ^{3} ) ( 4 x ^{5} + 7 )}{( x ^{3} ) ^{2}}

\frac{d}{d x} (4 x^{5} + 7) = 20 x^{4}

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{20 x ^{4} x ^{3} - 3 x ^{2} ( 4 x ^{5} + 7 )}{( x ^{3} ) ^{2}}

Simplify

\frac{20 x ^{4} x ^{3} - 3 x ^{2} ( 4 x ^{5} + 7 )}{( x ^{3} ) ^{2}} : \frac{8 x ^{5} - 21}{x ^{4}}

= \frac{8 x ^{5} - 21}{x ^{4}}

y^{^{''}} - 2 y^{^{'}} + y = \frac{( - 6 e ^{t} )}{t ^{2} + 1}

f (x) = x^{3} - 6 x^{2} - 34 x + 40, at x = 2

f (x) = x^{2} arcsin (3 x)

f (x) = x^{5} e^{x}

\frac{d r}{d θ} = (sin (π θ))^{4}

What is the derivative of (4x^5+7/(x^3)) ?
The derivative of (4x^5+7/(x^3)) is (8x^5-21)/(x^4)
What is the first derivative of (4x^5+7/(x^3)) ?
The first derivative of (4x^5+7/(x^3)) is (8x^5-21)/(x^4)