What is the integral of θtan(8)θ^2 ?

The integral of θtan(8)θ^2 is 1/4 tan(8)θ^4+C

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integral of θtan(8)θ^2

\int θ tan (8) θ^{2} d θ

\frac{1}{4} tan (8) θ^{4} + C

Solution steps

\int θ tan (8) θ^{2} d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= tan (8) \cdot \int θ θ^{2} d θ

Simplify

θ θ^{2} : θ^{3}

= tan (8) \cdot \int θ^{3} d θ

Apply the Power Rule

: \frac{θ ^{4}}{4}

= tan (8) \frac{θ ^{4}}{4}

Simplify

tan (8) \frac{θ ^{4}}{4} : \frac{1}{4} tan (8) θ^{4}

= \frac{1}{4} tan (8) θ^{4}

Add a constant to the solution

= \frac{1}{4} tan (8) θ^{4} + C

\frac{\partial}{\partial x} (e^{x y} ln (9 y))

\frac{d}{d x} (5 - \frac{2}{x})

\int_{3}^{\infty} \frac{ln ( x )}{x} d x

x \to 0 - lim (\frac{∣ x ∣}{x})

f (x) = 4 e^{x} cos (x), (0, 4)

What is the integral of θtan(8)θ^2 ?
The integral of θtan(8)θ^2 is 1/4 tan(8)θ^4+C