What is the integral of (x^3)/(x+3) ?

The integral of (x^3)/(x+3) is (x^3)/3-(3x^2)/2+9x-27ln|x+3|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^3)/(x+3)

\int \frac{x ^{3}}{x + 3} d x

\frac{x ^{3}}{3} - \frac{3 x ^{2}}{2} + 9 x - 27 ln ∣ x + 3 ∣ + C

Solution steps

\int \frac{x ^{3}}{x + 3} d x

Long division

\frac{x ^{3}}{x + 3} : x^{2} - 3 x + 9 - \frac{27}{x + 3}

= \int x^{2} - 3 x + 9 - \frac{27}{x + 3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 3 x d x + \int 9 d x - \int \frac{27}{x + 3} d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 9 d x = 9 x

\int \frac{27}{x + 3} d x = 27 ln ∣ x + 3 ∣

= \frac{x ^{3}}{3} - \frac{3 x ^{2}}{2} + 9 x - 27 ln ∣ x + 3 ∣

Add a constant to the solution

= \frac{x ^{3}}{3} - \frac{3 x ^{2}}{2} + 9 x - 27 ln ∣ x + 3 ∣ + C

\int \frac{x ^{2} + 1}{( x + 1 ) ^{2} ( x - 1 )} d x

\int \frac{1}{x ^{2} ( 1 + x ^{2} )} d x

\int \frac{3}{x ^{3} + 1} d x

\int \frac{x ^{3}}{9 + x ^{2}} d x

\int \frac{sin ( x ) cos ( x )}{1 + sin ^{4} ( x )} d x

What is the integral of (x^3)/(x+3) ?
The integral of (x^3)/(x+3) is (x^3)/3-(3x^2)/2+9x-27ln|x+3|+C