What is the integral of 3/(x(ln(x))^4) ?

The integral of 3/(x(ln(x))^4) is -1/(ln^3(x))+C

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integral of 3/(x(ln(x))^4)

\int \frac{3}{x ( ln ( x ) ) ^{4}} d x

- \frac{1}{ln ^{3} ( x )} + C

Solution steps

\int \frac{3}{x ( ln ( x ) ) ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{x ( ln ( x ) ) ^{4}} d x

Apply u-substitution

: \int \frac{1}{u ^{4}} d u

= 3 \cdot \int \frac{1}{u ^{4}} d u

Apply the Power Rule

: - \frac{1}{3 u ^{3}}

= 3 (- \frac{1}{3 u ^{3}})

Substitute back

u = ln (x)

= 3 (- \frac{1}{3 ln ^{3} ( x )})

Simplify

3 (- \frac{1}{3 ln ^{3} ( x )}) : - \frac{1}{ln ^{3} ( x )}

= - \frac{1}{ln ^{3} ( x )}

Add a constant to the solution

= - \frac{1}{ln ^{3} ( x )} + C

\int \frac{( x ) ^{3} - 1}{x + 1} d x

\int 2 (x^{2} + x + 2) e^{- 2 x} d x

cos^{3} (x)

\int (t er m o, i) d x

What is the integral of 3/(x(ln(x))^4) ?
The integral of 3/(x(ln(x))^4) is -1/(ln^3(x))+C