What is the integral of (csc^2(y)+1) ?

The integral of (csc^2(y)+1) is -cot(y)+y+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (csc^2(y)+1)

\int (csc^{2} (y) + 1) d y

- cot (y) + y + C

Solution steps

\int csc^{2} (y) + 1 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int csc^{2} (y) d y + \int 1 d y

\int csc^{2} (y) d y = - cot (y)

\int 1 d y = y

= - cot (y) + y

Add a constant to the solution

= - cot (y) + y + C

\int e^{x} sin (a x) d x

\int sin (x) cos (\frac{x}{2}) d x

\int (\frac{6 t - 8}{( t - 3 ) ^{3}}) d t

\int 2 x sin^{2} (x) + 2 x cos^{2} (x) d x

\int 3 x (sin^{2} (x) + cos^{2} (x)) d x

What is the integral of (csc^2(y)+1) ?
The integral of (csc^2(y)+1) is -cot(y)+y+C