Solution
Solution
Solution steps
Complete the square
Apply u-substitution
Apply Trigonometric Substitution
Use the common integral:
Substitute back
Simplify
Add a constant to the solution
Popular Examples
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Frequently Asked Questions (FAQ)
What is the integral of 1/(sqrt(x^2+4x+6)) ?
The integral of 1/(sqrt(x^2+4x+6)) is ln| 1/(sqrt(2))(x+2)+sqrt(1/2 (x^2+4x+6))|+C