What is the derivative of y=e^{2e^x} ?

The derivative of y=e^{2e^x} is 2e^{2e^x+x}

What is the first derivative of y=e^{2e^x} ?

The first derivative of y=e^{2e^x} is 2e^{2e^x+x}

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derivative of

y = e^{2 e^{x}}

2 e^{2 e^{x} + x}

Solution steps

\frac{d}{d x} (e^{2 e^{x}})

Apply the chain rule:

e^{2 e^{x}} \frac{d}{d x} (2 e^{x})

= e^{2 e^{x}} \frac{d}{d x} (2 e^{x})

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

= e^{2 e^{x}} \cdot 2 e^{x}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{2 e^{x}} e^{x} = e^{2 e^{x} + x}

= 2 e^{2 e^{x} + x}

x \to 3 lim (x^{2} - x - 6)

\int_{1}^{8} 7 \frac{ln ( x )}{x ^{2}} d x

\frac{s - 2}{s ^{2} - 7 s + 6}

x^{- 6} + e^{2 x}

\frac{d y}{d x} + 2 x y = x

What is the derivative of y=e^{2e^x} ?
The derivative of y=e^{2e^x} is 2e^{2e^x+x}
What is the first derivative of y=e^{2e^x} ?
The first derivative of y=e^{2e^x} is 2e^{2e^x+x}