What is the integral of (27t^3-1)/(\sqrt[3]{t)} ?

The integral of (27t^3-1)/(\sqrt[3]{t)} is 81/11 t^{11/3}-3/2 t^{2/3}+C

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integral of (27t^3-1)/(\sqrt[3]{t)}

\frac{81}{11} t^{\frac{11}{3}} - \frac{3}{2} t^{\frac{2}{3}} + C

Solution steps

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 27 t^{\frac{8}{3}} d t = \frac{81}{11} t^{\frac{11}{3}}

= \frac{81}{11} t^{\frac{11}{3}} - \frac{3}{2} t^{\frac{2}{3}}

Add a constant to the solution

= \frac{81}{11} t^{\frac{11}{3}} - \frac{3}{2} t^{\frac{2}{3}} + C

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What is the integral of (27t^3-1)/(\sqrt[3]{t)} ?
The integral of (27t^3-1)/(\sqrt[3]{t)} is 81/11 t^{11/3}-3/2 t^{2/3}+C