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Popular >

integral of-0.1x+40

Solution

\int - 0.1 x + 40 d x

Solution

- 0.05 x^{2} + 40 x + C

Solution steps

\int - 0.1 x + 40 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 0.1 x d x + \int 40 d x

\int 0.1 x d x = 0.05 x^{2}

\int 40 d x = 40 x

= - 0.05 x^{2} + 40 x

Add a constant to the solution

= - 0.05 x^{2} + 40 x + C

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Frequently Asked Questions (FAQ)

What is the integral of-0.1x+40 ?
The integral of-0.1x+40 is -0.05x^2+40x+C