What is the integral of (x^3+3x^2+9)/(x+2) ?

The integral of (x^3+3x^2+9)/(x+2) is -3x^2-12x+13ln|x+2|+1/3 (x+2)^3+3/2 (x+2)^2-12+C

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integral of (x^3+3x^2+9)/(x+2)

\int \frac{x ^{3} + 3 x ^{2} + 9}{x + 2} d x

- 3 x^{2} - 12 x + 13 ln ∣ x + 2 ∣ + \frac{1}{3} (x + 2)^{3} + \frac{3}{2} (x + 2)^{2} - 12 + C

Solution steps

\int \frac{x ^{3} + 3 x ^{2} + 9}{x + 2} d x

Expand

\frac{x ^{3} + 3 x ^{2} + 9}{x + 2} : \frac{x ^{3}}{x + 2} + \frac{3 x ^{2}}{x + 2} + \frac{9}{x + 2}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x ^{3}}{x + 2} d x + \int \frac{3 x ^{2}}{x + 2} d x + \int \frac{9}{x + 2} d x

\int \frac{x ^{3}}{x + 2} d x = - 3 x^{2} + \frac{1}{3} (x + 2)^{3} - 8 ln ∣ x + 2 ∣ + 12

\int \frac{3 x ^{2}}{x + 2} d x = 3 (\frac{( x + 2 ) ^{2}}{2} - 4 (x + 2) + 4 ln ∣ x + 2 ∣)

\int \frac{9}{x + 2} d x = 9 ln ∣ x + 2 ∣

= - 3 x^{2} + \frac{1}{3} (x + 2)^{3} - 8 ln ∣ x + 2 ∣ + 12 + 3 (\frac{( x + 2 ) ^{2}}{2} - 4 (x + 2) + 4 ln ∣ x + 2 ∣) + 9 ln ∣ x + 2 ∣

Simplify

- 3 x^{2} + \frac{1}{3} (x + 2)^{3} - 8 ln ∣ x + 2 ∣ + 12 + 3 (\frac{( x + 2 ) ^{2}}{2} - 4 (x + 2) + 4 ln ∣ x + 2 ∣) + 9 ln ∣ x + 2 ∣ : - 3 x^{2} - 12 x + 13 ln ∣ x + 2 ∣ + \frac{1}{3} (x + 2)^{3} + \frac{3}{2} (x + 2)^{2} - 12

= - 3 x^{2} - 12 x + 13 ln ∣ x + 2 ∣ + \frac{1}{3} (x + 2)^{3} + \frac{3}{2} (x + 2)^{2} - 12

Add a constant to the solution

= - 3 x^{2} - 12 x + 13 ln ∣ x + 2 ∣ + \frac{1}{3} (x + 2)^{3} + \frac{3}{2} (x + 2)^{2} - 12 + C

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What is the integral of (x^3+3x^2+9)/(x+2) ?
The integral of (x^3+3x^2+9)/(x+2) is -3x^2-12x+13ln|x+2|+1/3 (x+2)^3+3/2 (x+2)^2-12+C