What is the integral of (4x+7)^{11} ?

The integral of (4x+7)^{11} is 1/48 (4x+7)^{12}+C

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integral of (4x+7)^{11}

\int (4 x + 7)^{11} d x

\frac{1}{48} (4 x + 7)^{12} + C

Solution steps

\int (4 x + 7)^{11} d x

Apply u-substitution

: \int \frac{u ^{11}}{4} d u

= \int \frac{u ^{11}}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int u^{11} d u

Apply the Power Rule

: \frac{u ^{12}}{12}

= \frac{1}{4} \cdot \frac{u ^{12}}{12}

Substitute back

u = 4 x + 7

= \frac{1}{4} \cdot \frac{( 4 x + 7 ) ^{12}}{12}

Simplify

\frac{1}{4} \cdot \frac{( 4 x + 7 ) ^{12}}{12} : \frac{1}{48} (4 x + 7)^{12}

= \frac{1}{48} (4 x + 7)^{12}

Add a constant to the solution

= \frac{1}{48} (4 x + 7)^{12} + C

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What is the integral of (4x+7)^{11} ?
The integral of (4x+7)^{11} is 1/48 (4x+7)^{12}+C