What is the integral of y^3sqrt(y) ?

The integral of y^3sqrt(y) is 2/9 y^{9/2}+C

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integral of y^3sqrt(y)

\int y^{3} y d y

\frac{2}{9} y^{\frac{9}{2}} + C

Solution steps

\int y^{3} y d y

Simplify

y^{3} y : y^{\frac{7}{2}}

= \int y^{\frac{7}{2}} d y

Apply the Power Rule

: \frac{2}{9} y^{\frac{9}{2}}

= \frac{2}{9} y^{\frac{9}{2}}

Add a constant to the solution

= \frac{2}{9} y^{\frac{9}{2}} + C

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What is the integral of y^3sqrt(y) ?
The integral of y^3sqrt(y) is 2/9 y^{9/2}+C