What is the integral of 4xsqrt(1+x^2) ?

The integral of 4xsqrt(1+x^2) is 4/3 (1+x^2)^{3/2}+C

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integral of 4xsqrt(1+x^2)

\int 4 x 1 + x^{2} d x

\frac{4}{3} (1 + x^{2})^{\frac{3}{2}} + C

Solution steps

\int 4 x 1 + x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int x 1 + x^{2} d x

Apply u-substitution

: \int u^{2} d u

= 4 \cdot \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= 4 \cdot \frac{u ^{3}}{3}

Substitute back

u = 1 + x^{2}

= 4 \cdot \frac{( 1 + x ^{2} ) ^{3}}{3}

Simplify

4 \cdot \frac{( 1 + x ^{2} ) ^{3}}{3} : \frac{4}{3} (1 + x^{2})^{\frac{3}{2}}

= \frac{4}{3} (1 + x^{2})^{\frac{3}{2}}

Add a constant to the solution

= \frac{4}{3} (1 + x^{2})^{\frac{3}{2}} + C

\int \frac{x}{1 - x} d x

\int (e^{3 x} + \frac{1}{x ^{3}} - 7 x^{\frac{3}{2}}) d x

\frac{1}{( 1 - x ) ^{2}}

\int (sec^{2} (x)) (1 + tan (x)) d x

What is the integral of 4xsqrt(1+x^2) ?
The integral of 4xsqrt(1+x^2) is 4/3 (1+x^2)^{3/2}+C