What is the integral of 1/(x^2)cos(2/x) ?

The integral of 1/(x^2)cos(2/x) is -1/2 sin(2/x)+C

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integral of 1/(x^2)cos(2/x)

\int \frac{1}{x ^{2}} cos (\frac{2}{x}) d x

- \frac{1}{2} sin (\frac{2}{x}) + C

Solution steps

\int \frac{1}{x ^{2}} cos (\frac{2}{x}) d x

Apply u-substitution

: \int - \frac{cos ( u )}{2} d u

= \int - \frac{cos ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= - \frac{1}{2} sin (u)

Substitute back

u = \frac{2}{x}

= - \frac{1}{2} sin (\frac{2}{x})

Add a constant to the solution

= - \frac{1}{2} sin (\frac{2}{x}) + C

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What is the integral of 1/(x^2)cos(2/x) ?
The integral of 1/(x^2)cos(2/x) is -1/2 sin(2/x)+C