What is the integral of (3x)/(\sqrt[3]{t^2+3)} ?

The integral of (3x)/(\sqrt[3]{t^2+3)} is 3/(\sqrt[3]{3+t^2)}*(x^2)/2+C

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integral of (3x)/(\sqrt[3]{t^2+3)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{x ^{2}}{2}

Add a constant to the solution

\int \frac{1}{2 x ^{2} + 8} d x

\int \frac{y}{2 - y} d y

\int \frac{sin ( x ) cos ( x )}{1 + cos ^{2} ( x )} d x

\int arccos^{2} (x) d x

\int - z sin (z) + cos (z) d z

What is the integral of (3x)/(\sqrt[3]{t^2+3)} ?
The integral of (3x)/(\sqrt[3]{t^2+3)} is 3/(\sqrt[3]{3+t^2)}*(x^2)/2+C